CTHH: R2CO3 (a mol), R2S (b mol)
=> 2a.MR + 60a + 2b.MR + 32b = 174 (1)
nKOH = 0,5.3 = 1,5 (mol)
PTHH: \(R_2CO_3+2HCl\rightarrow2RCl+CO_2+H_2O\)
a-------------------------->a
\(R_2S+2HCl\rightarrow2RCl+H_2S\)
b----------------------b
\(KOH+CO_2\rightarrow KHCO_3\)
a<------a
\(KOH+H_2S\rightarrow KHS+H_2O\)
b<-----b
=> a + b = 1,5
(1) => 3.MR + 28a + 48 = 174
=> 3.MR + 28a = 126
Mà 0 < a < 1,5
=> 28 < MR < 42
=> R là K
Ta có: \(\left\{{}\begin{matrix}138a+110b=174\\a+b=1,5\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}a=\dfrac{9}{28}\left(mol\right)\\b=\dfrac{33}{28}\left(mol\right)\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\%n_{K_2CO_3}=\dfrac{\dfrac{9}{28}}{1,5}.100\%=21,43\%\%\\\%n_{K_2S}=\dfrac{\dfrac{33}{28}}{1,5}.100\%=78,57\%\end{matrix}\right.\)
