\(e,\left(-2\right)+\dfrac{-5}{4}+\dfrac{1}{8}=\dfrac{-16}{8}+\dfrac{-10}{8}+\dfrac{1}{8}=\dfrac{-25}{8}\)
\(\left(-2\right)+\dfrac{-5}{4}+\dfrac{1}{8}=\dfrac{-8}{4}+\dfrac{-5}{4}+\dfrac{1}{8}=\dfrac{-13}{4}+\dfrac{1}{8}=\dfrac{-26}{8}+\dfrac{1}{8}=\dfrac{-25}{8}\)