\(\dfrac{1}{3}x-\dfrac{2}{3}=\dfrac{1}{2}\left(\dfrac{1}{4}-4\right)\)
\(\Rightarrow\dfrac{1}{3}x-\dfrac{2}{3}=\dfrac{1}{2}.\left(-\dfrac{15}{4}\right)\)
\(\Rightarrow\dfrac{1}{3}x-\dfrac{2}{3}=-\dfrac{15}{8}\)
\(\Rightarrow\dfrac{1}{3}x=-\dfrac{29}{24}\Rightarrow x=-\dfrac{29}{8}\)
\(\dfrac{1}{3}x-\dfrac{2}{3}=\dfrac{1}{2}\left(\dfrac{1-4.4}{4}\right)\\ \dfrac{1}{3}x-\dfrac{2}{3}=\dfrac{1}{2}\left(-\dfrac{15}{4}\right)\\ \dfrac{1}{3}x-\dfrac{2}{3}=-\dfrac{15}{8}\\ \dfrac{1}{3}x=\left(-\dfrac{15}{8}\right)+\dfrac{2}{3}\\ \dfrac{1}{3}x=\dfrac{\left(-15\right).3+2.8}{24}\\ \dfrac{1}{3}x=-\dfrac{29}{24}\\ x=-\dfrac{29}{24}:\dfrac{1}{3}\\ x=-\dfrac{29}{24}.\dfrac{3}{1}\\ x=-\dfrac{29}{8}\)
`1/3x -2/3 = 1/2 . (1/4-4)`
`1/3x -2/3 = 1/2.(1/4-16/4)`
`1/3x -2/3 = 1/2 . (-15)/4`
`1/3 x - 2/3 = (-15)/8`
`1/3 x = (-15)/8 + 2/3`
`1/3x = (-29)/24`
`x = (-29)/24 : 1/3`
`x = (-29)/24xx 3`
`x=(-29)/8`
Vậy `x=(-29)/8`
