Question

Answer 1

phân tích đa thức thành nhân tử

 

Answer 2

`m,xz-yz-x^2 +2xy-y^2`

`=z(x-y)-(x^2 -2xy+y^2)`

`=z(x-y)-(x-y)^2`

`=(x-y)[z-(x-y)`

`=(x-y)(z-x+y)`

`p,x^2 +8x+15`

`=x^2 +3x+5x+15`

`=x(x+3)+5(x+3)`

`=(x+3)(x+5)`

`k,x^2 -x-12`

`=x^2 -4x+3x-12`

`=x(x-4)+3(x-4)`

`=(x+3)(x-4)`

Answer 3

phân tik đk ạ.-.

m ) .

= \(z\left(x-y\right)-\left(x-y\right)^2\)

= \(z\left(x-y\right)-\left(x-y\right)\left(x-y\right)\)

= \(\left(x-y\right)\left(z-x+y\right)\)

p ) .

= \(x^2+8x+16-1\)

= \(x^2+8x+4^2-1^2\)

= \(\left(x+4\right)^2-1^2=\left(x+4+1\right)\left(x+4-1\right)=\left(x+5\right)\left(x+3\right)\)

Answer 4

`m, xz - yz - x^2 + 2xy - y^2`

`= z(x-y) -(x-y)^2`

`= (x-y)(z - x + y)`

`p, x^2 + 8x + 15`

`= x^2 + 8x + 16 - 1`

`= (x+4)^2 - 1`

`= (x+3)(x+5)`

`k, x^2 - x - 12`

`= x^2 - 4x + 3x - 12`

`= (x+3)(x-4)`