Cốc 1:
\(n_{Zn}=\dfrac{16,25}{65}=0,25\left(mol\right)\)
PTHH: \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\uparrow\)
0,25----------------------------->0,25
\(\rightarrow m_{cốc\left(1\right)}=16,25+m_{H_2SO_4}-0,25.2=15,75+m_{H_2SO_4}\left(g\right)\)
- Cốc 2:
\(n_{Al}=\dfrac{m}{27}\left(mol\right)\)
PTHH: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\uparrow\)
\(\dfrac{m}{27}\)------------------------------------->\(\dfrac{m}{18}\)
\(\rightarrow m_{cốc\left(2\right)}=m+m_{HCl}-\dfrac{m}{18}.2=\dfrac{8m}{9}+m_{HCl}\)
Do mcốc (1) = mcốc (2)
\(\rightarrow15,75+m_{H_2SO_4}=\dfrac{8m}{9}+m_{HCl}\\ \Leftrightarrow15,75=\dfrac{8m}{9}\left(do:m_{HCl}=m_{H_2SO_4}\right)\\ \Leftrightarrow m=17,71875\left(g\right)\)
