Question

 

Answer 1

`x-2019 2/13=3 7/26 +4 7/52`

`x-2019 8/52=3 14/52 + 4 7/52`

`x=3 14/52 +4 7/52+2019 8/52`

`x=(2019+3+4)+((14+7+8)/52)`

`x=2026+29/52`

`x=2026 29/52`

Answer 2

\(x-2019\dfrac{2}{13}=3\dfrac{7}{26}+4\dfrac{7}{52}\)

\(x-2019\dfrac{2}{13}=\left(3+4\right)\left(\dfrac{7}{26}+\dfrac{7}{52}\right)\)

\(x-2019\dfrac{2}{13}=7\dfrac{21}{52}\)

\(x=7\dfrac{23}{52}+2019\dfrac{2}{13}\)

\(x=\left(7+2019\right)\left(\dfrac{23}{52}+\dfrac{2}{13}\right)\)

\(x=2026\dfrac{29}{52}\)

Answer 3