x(1+1/2+1/3+1/6)=-12
x.2=-12
x=-12:2
x=-6
\(x+\dfrac{x}{2}+\dfrac{x}{3}+\dfrac{x}{6}=-12\\ \Leftrightarrow x\left(1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)=-12\\ \Leftrightarrow x.2=-12\\ \Leftrightarrow x=-6\)
Vậy `x=-6`
\(x+\dfrac{x}{2}+\dfrac{x}{3}+\dfrac{x}{6}=-12\)
\(x.\left(1-\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)=-12\)
\(x.2=-12\)
\(x=-12:2\)
\(x=-6\)