a, ta có:
1/3^2<1/2.3
1/4^2<1/3.2
...
1/200^2<1/199.200
=>1/3^2+1/4^2+...+1/200^2<1/2.3+1/3.4+...+1/199.200
=>A<1/2-1/3+1/3-1/4+...+1/199-1/200
=>A<1/2-1/200<1/2
=>A<1/2
b,ta có:
B=2(1/2^2+1/3^2+..+1/200^2)
B>2(1/2.3+1/3.4+...+1/200.201)
B>2(1/2-1/3+1/3-1/4+...+1/200-1/201)
B>2(1/2-1/201)
B>199/201>9/20
=>B>9/20