m ).
\(=\dfrac{5}{2}x\dfrac{8}{5}=\dfrac{40}{10}=4\)
n ) .
\(=\dfrac{-3}{8}x\dfrac{2}{1}=\dfrac{-6}{8}=-\dfrac{3}{4}\)
p ) .
\(=\dfrac{9}{5}x\dfrac{-5}{3}=\dfrac{-45}{15}=-3\)
q ) .
\(=-15x\dfrac{-2}{3}=\dfrac{30}{3}=10\)
\(m.2\dfrac{1}{2}.1\dfrac{3}{5}=\dfrac{5}{2}.\dfrac{8}{5}=\dfrac{40}{10}=4\)
\(n.\dfrac{-3}{8}:\dfrac{1}{2}=\dfrac{-3}{8}.2=-\dfrac{3}{4}\)
\(p.\dfrac{9}{5}:\dfrac{-3}{5}=\dfrac{9}{5}\times\dfrac{-5}{3}=-3\)
\(q.-15:\dfrac{-3}{2}=-15\times\dfrac{-2}{3}=10\)
m). \(2\dfrac{1}{2}.1\dfrac{3}{5}=\dfrac{5}{2}.\dfrac{8}{5}=\dfrac{40}{10}=4\)
n). \(\dfrac{-3}{8}:\dfrac{1}{2}=\dfrac{-3}{8}.\dfrac{2}{1}=\dfrac{-6}{8}=\dfrac{-3}{4}\)
p). \(\dfrac{9}{5}:\dfrac{-3}{5}=\dfrac{9}{5}.\dfrac{-5}{3}=\dfrac{-45}{15}=\left(-15\right)\)
q). \(-15:\dfrac{-3}{2}=\dfrac{-15}{1}:\dfrac{-3}{2}=\dfrac{-15}{1}.\dfrac{-2}{3}=\dfrac{30}{3}=10\)
\(m)2\dfrac{1}{2}.1\dfrac{3}{5}=\dfrac{5}{2}.\dfrac{8}{5}=\dfrac{5.8}{2.5}=\dfrac{40}{10}=4\)
\(n)\dfrac{-3}{8}:\dfrac{1}{2}=\dfrac{-3}{8}.\dfrac{2}{1}=\dfrac{\left(-3\right).2}{8.1}=\dfrac{-6}{8}=-\dfrac{3}{4}\)
\(p)\dfrac{9}{5}:\dfrac{-3}{5}=\dfrac{9}{5}.-\dfrac{5}{3}=\dfrac{9.\left(-5\right)}{5.3}=\dfrac{-45}{15}=-3\)
\(q)-15:\dfrac{-3}{2}=\dfrac{-15}{1}.\dfrac{-2}{3}=\dfrac{\left(-15\right).\left(-2\right)}{1.3}=\dfrac{30}{3}=10.\)
