\(g.\dfrac{-5}{6}-\left(-1\right)=\dfrac{-5}{6}+1=\dfrac{-5}{6}+\dfrac{6}{6}=\dfrac{1}{6}\)
\(h.-3\dfrac{1}{2}-1\dfrac{1}{6}=\left[\left(-3-1\right)\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\right]=-4\dfrac{1}{3}\)
\(i.\dfrac{3}{5}.\dfrac{1}{2}=\dfrac{3}{10}\)
\(k.\dfrac{-1}{3}.\dfrac{5}{8}=\dfrac{-5}{24}\)
\(g)\dfrac{-5}{6}-\left(-1\right)=\dfrac{-5}{6}+1=\dfrac{1}{6}\)
\(h)-3\dfrac{1}{2}-1\dfrac{1}{6}=-\dfrac{7}{2}-\dfrac{7}{6}=-\dfrac{21}{6}-\dfrac{7}{6}=-\dfrac{14}{3}\)
\(i)\dfrac{3}{5}.\dfrac{1}{2}=\dfrac{3.1}{5.2}=\dfrac{3}{10}\)
\(k)\dfrac{-1}{3}.\dfrac{5}{8}=\dfrac{\left(-1\right).5}{3.8}=-\dfrac{5}{24}.\)
