\(\dfrac{16,2\times\left(3,7+5,7\right)-7,8\times\left(4,8+6,8\right)}{\left(13,4-12,6\right)+\left(12,3-11,5\right)+\left(11,2-10,4\right)}\)
\(\dfrac{16,2\times9,4-7,8\times9,4}{0,8+0,8+0,8}=\dfrac{9,4\times\left(16,2-7,8\right)}{3\times0,8}=\dfrac{9,4\times8,4}{2,4}=32,9\)
`#Ya`