a,=15/17.(45/33-12/33)
=15/17.1
=15/17
b,=15/16.8/3.3/4
=5/2.3/4
=15/8
\(\dfrac{15}{17}x\left(\dfrac{45}{33}-\dfrac{12}{33}\right)=\dfrac{15}{17}x1=\dfrac{15}{17}\)
\(\dfrac{15}{16}x\dfrac{8}{3}x\dfrac{3}{4}=\dfrac{15x8x3}{16x3x4}=\dfrac{15}{8}\)
b.\(\dfrac{15}{17}\) b.\(\dfrac{5}{2}\)x\(\dfrac{3}{4}\)=\(\dfrac{15}{8}\)
`b)15/17xx45/33-15/17xx12/33=15/17xx(45/33-12/33)=15/17xx33/33=15/17`
`b)15/16:3/8xx3/4=15/16xx8/3xx3/4=[15xx8xx3]/[2xx8xx3xx4]=15/8`
A)
=15/17.(45/33-12/33)
=15/17.1
=15/17
B)
=15/16.8/3.3/4
=45/128.3/4
=135/512
