Question

Answer 1

TH1 \(\Rightarrow\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\)Theo tc dãy tỉ số bằng nhau

 \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}=\dfrac{x-y+z}{2-3+5}=1\Rightarrow x=2;y=3;z=5\)

TH2 \(\Rightarrow-\dfrac{x}{2}=-\dfrac{y}{3}=\dfrac{-z}{5}\)Theo tc dãy tỉ số bằng nhau 

\(-\dfrac{x}{2}=-\dfrac{y}{3}=-\dfrac{z}{5}=\dfrac{-x+y-z}{2-3+5}=\dfrac{-4}{4}=-1\Rightarrow x=2;y=3;z=5\)