Question

Answer 1

mạch cầu tương đương ( (R1ntR2) song song  (R3ntR4) )ntR5

R12=R1+R2=80 ôm

R34=R3+R4=80 ôm

R1234=\(\dfrac{R12.R34}{R12+R34}\)=\(\dfrac{80.80}{80+80}\)=40 ôm 

Rtđ=1234+R5=40+10=50 ôm

 

Answer 2

 

\(R_{tđ}=\left(\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}\right)+R_5=10,12\Omega\)