Question

Answer 1

`x/3 - (2x + 1)/6 = x/6 - x`

`<=> x/3 + (-2x - 1)/6 = x/6 - x`

`<=> (2x)/6 + (2x - 1)/6 = x/6 - x`

`<=> (2x - 2x - 1)/6 = x/6 - x`

`<=> -1/6 = x/6 - x`

`=> x = 1/5`

Vậy `S = {1/5}`

Answer 2

x/3 - 2x+1/6 = x/6 - x

<=> x.2/6 - 2x+1/6 = x/6 - x.6/6

<=> 2x - 2x + 1 = x - 6x

<=> 2x-2x-x+6x=-1

<=> 5x = -1

<=> x= -1/5