\(A=x\left(x-3\right)\left(x-4\right)\left(x-7\right)=\left(x^2-7x\right)\left(x^2-7x+12\right)=\left(x^2-7x\right)^2+12\left(x^2-7x\right)\left(x^2-7x\right)^2+2.6\left(x^2-7x\right)+36-36=\left(x^2+7x+6\right)^2-36\ge-36\)
\(A=-36\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-6\end{matrix}\right.\)
-Vậy \(A_{min}=-36\)

