Question

Answer 1

`[ 2x + 2 ] / 3 < 2 + [ x - 2 ] / 2`

`<=> [ 2 ( 2x + 2 ) ] / 6 < [ 12 + 3 ( x -  2) ] / 6`

`<=> 4x + 4 < 12 + 3x - 6`

`<=> 4x - 3x < 12 - 6 - 4`

`<=> x < 2`

Vậy `S = { x | x < 2}`

Answer 2

\(\dfrac{2x+2}{3}< 2+\dfrac{x-2}{2}\) \(\Leftrightarrow\) 2(2x+2) < 6.2+3(x-2) \(\Leftrightarrow\) 4x+4 < 12+3x-6 \(\Leftrightarrow\) x<2.

Answer 3

⇔\(\dfrac{2\left(2x+2\right)}{6}\)<12+\(\dfrac{3\left(x-2\right)}{6}\)

⇔2(2x+2)<12+3(x-2)

⇔4x+4<12+3x-6

⇔x<2