Gọi số mol SO2, O2 là a, b (mol)
Có: \(M_A=\dfrac{64a+32b}{a+b}=24.2=48\left(g/mol\right)\)
=> 16a = 16b => a = b
=> \(\%V_{SO_2\left(A\right)}=\%V_{O_2\left(A\right)}=50\%\)
PTHH: 2SO2 + O2 --to,V2O5--> 2SO3
Bđ a b 0
Pư: x--->0,5x-------------->x
Sau pư:(a-x) (b-0,5x) x
=> \(M_B=\dfrac{64a+32b}{\left(a-x\right)+\left(b-0,5x\right)+x}=30.2=60\left(g/mol\right)\)
=> \(\dfrac{96a}{2a-0,5x}=60\)
=> 96a = 120a - 30x
=> x = 0,8a
B chứa \(\left\{{}\begin{matrix}SO_2:0,2a\left(mol\right)\\O_2:0,6a\left(mol\right)\\SO_3:0,8a\left(mol\right)\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}\%V_{SO_2}=\dfrac{0,2a}{1,6a}.100\%=12,5\%\\\%V_{O_2}=\dfrac{0,6a}{1,6a}.100\%=37,5\%\\\%V_{SO_3}=\dfrac{0,8a}{1,6a}.100\%=50\%\end{matrix}\right.\)
