Question

Answer 1

â)\(A=\left(-\dfrac{1}{3}\cdot\dfrac{1}{2}.48\right)\left(x^2x.x^2\right)\left(y^4y^3\right)=-8x^5y^7\)

bậc : 5 + 7 = 12

b) thay x=1/2 ,  y = -1 và đơn thức A ta ddc

\(A=-8.\left(\dfrac{1}{2}\right)^5.\left(-1\right)^7=-\dfrac{8.1}{32}.\left(-1\right)=\dfrac{1}{4}\)

Answer 2

a,

\(A = \dfrac{1}{2}x^2 . 48xy^4 . ( -\dfrac{1}{3} x^2y^3 )\)

    \(= ( \dfrac{1}{2} . \dfrac{-1}{3} . 48 ) . ( x^2 . x . x^2 ) . ( y^4 . y^3 )\)

    \(= -8x^5y^7\)

Bậc : 12

b, 

Thay \(x = \dfrac{1}{2} ; y=-1\) vào A ta có :

\(A = -8 . ( \dfrac{1}{2} )^5 . ( -1 )^7 = \dfrac{1}{4}\)