\(x+y-\dfrac{xy}{2}=0\Leftrightarrow x+y=\dfrac{xy}{2}\)
-Áp dụng BĐT AM-GM ta có:
\(x+y\ge2\sqrt{xy}\Rightarrow\dfrac{xy}{2}\ge2\sqrt{xy}\)
\(\Leftrightarrow xy\ge4\sqrt{xy}\)
\(\Leftrightarrow\dfrac{xy}{\sqrt{xy}}\ge4\Leftrightarrow\sqrt{xy}\ge4\Leftrightarrow xy\ge16\)
-Áp dụng BĐT AM-GM ta có:
\(\left(x+y\right)^2\ge4xy\ge4.16=64\Rightarrow x+y\ge8\)
-Dấu "=" xảy ra khi \(x=y=4\)

