b. (x - 1).(5x + 3) = (3x - 8).(x - 1)
<=> (x - 1).(5x + 3) - (3x - 8).(x - 1) = 0
<=> (x - 1).[(5x + 3) - (3x - 8)] = 0
<=> (x - 1).(5x + 3 - 3x + 8) = 0
<=> (x - 1).(2x + 11) = 0
<=> x - 1 = 0 hoặc 2x + 11 = 0
<=> x = 1 hoặc x = -5,5
Vậy S = { 1;-5,5 }