Question

Answer 1

1) 

a) Gọi số mol Mg, Al, Zn là a, b,c (mol)

=> \(\left\{{}\begin{matrix}24a+27b+65c=19,46\left(1\right)\\24a=27b\left(2\right)\end{matrix}\right.\)

\(n_{H_2}=\dfrac{16,352}{22,4}=0,73\left(mol\right)\)

PTHH: Mg + 2HCl --> MgCl₂ + H₂

              a--->2a--------------->a

            2Al + 6HCl --> 2AlCl₃ + 3H₂

              b-->3b-------------->1,5b

            Zn + 2HCl --> ZnCl₂ + H₂

             c---->2c------------>c

=> a + 1,5b + c = 0,73 (3)

(1)(2)(3) => a = 0,27 (mol); b = 0,24 (mol); c = 0,1 (mol)

\(\left\{{}\begin{matrix}\%m_{Mg}=\dfrac{0,27.24}{19,46}.100\%=33,3\%\\\%m_{Al}=\dfrac{0,24.27}{19,46}.100\%=33,3\%\\\%m_{Zn}=\dfrac{0,1.65}{19,46}.100\%=33,4\%\end{matrix}\right.\)

b) n_HCl = 2a + 3b + 2c = 1,46 (mol)

=> \(V_{dd.HCl}=\dfrac{1,46}{2}=0,73\left(l\right)\)