\(\dfrac{9a+4b}{17}\in Z\Rightarrow\dfrac{3\left(9a+4b\right)}{17}\in Z\Rightarrow\dfrac{27a+12b}{17}\in Z\)
\(\Rightarrow\dfrac{17\left(a+b\right)+10a-5b}{17}\in Z\Rightarrow17-\dfrac{5\left(-2a+b\right)}{17}\in Z\)
\(\Rightarrow\dfrac{5\left(-2a+b\right)}{17}\in Z\)
Mà 5 và 17 nguyên tố cùng nhau
\(\Rightarrow\dfrac{-2a+b}{17}\in Z\)

