-BĐT Caushy: \(4ab\le\left(a+b\right)^2\Leftrightarrow4ab\le1\Leftrightarrow ab\le\dfrac{1}{4}\)
\(a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)=a^2-ab+b^2=\left(a+b\right)^2-3ab=1-3ab\ge1-3.\dfrac{1}{4}=\dfrac{1}{4}\)
-Dấu bằng xảy ra \(\Leftrightarrow a=b=\dfrac{1}{2}\)

