a) \(\overline{M}=\dfrac{0,3.44+0,5.64+0,2.32+1.28}{0,3+0,5+0,2+1}=39,8\left(g/mol\right)\)
=> \(d_{A/H_2}=\dfrac{39,8}{2}=19,9\)
b) \(V_A=22,4\left(0,3+0,5+0,2+1\right)=44,8\left(l\right)\)
c)
PTHH: Ca(OH)2 + CO2 --> CaCO3 + H2O
0,3------>0,3
Ca(OH)2 + SO2 --> CaSO3 + H2O
0,5---->0,5
=> m = 0,3.100 + 0,5.120 = 90 (g)
V = 44,8 - 0,3.22,4 - 0,5.22,4 = 26,88 (l)
