đkxđ : x khác 0
<=> \(5x+\dfrac{2x}{25}+4x+x+2x=\dfrac{20}{3}\)
<=> \(\dfrac{2x}{25}+12x=\dfrac{20}{3}\)
<=> \(\dfrac{6x}{75}+\dfrac{900x}{75}-\dfrac{500}{75}=0\)
<=> \(6x+900x-500=0\)
<=> \(906x-500=0\)
<=> 906x = 500
=> \(x=\dfrac{500}{906}=\dfrac{250}{453}\left(tm\right)\)
Vậy...
4 và 5