\(m_{NaOH}=\dfrac{8.400}{100}=32\left(g\right)\)
\(a,m_{dd}=200+400=600\left(g\right)\\ C\%_{NaOH}=\dfrac{32}{600}=5,33\%\\ b,C\%_{NaOH}=\dfrac{32}{600}=5,33\%\\ c,C\%_{NaOH}=\dfrac{200,12\%+32}{200+300}=11,2\%\)
\(d,n_{Na_2O}=\dfrac{6,2}{62}=0,1\left(mol\right)\\ n_{NaOH}=n_{Na_2O}=0,1\left(mol\right)\\ C\%_{NaOH}=\dfrac{0,1.40+32}{400+6,2}=8,86\%\\ e,C\%_{NaOH}=\dfrac{32+10}{400+10}=10,24\%\)
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