Question

Answer 1

a) 

\(n_{HCl\left(A\right)}=\dfrac{7,3}{36,5}=0,2\left(mol\right)\)

\(n_{HCl\left(B\right)}=\dfrac{58,4}{36,5}=1,6\left(mol\right)\)

=> \(C_{M\left(C\right)}=\dfrac{0,2+1,6}{3}=0,6M\)

b)

Có: \(\left\{{}\begin{matrix}C_{M\left(A\right)}=\dfrac{0,2}{V_1}M\\C_{M\left(B\right)}=\dfrac{1,6}{V_2}M\end{matrix}\right.\)

=> \(\dfrac{1,6}{V_2}-\dfrac{0,2}{V_1}=0,6\)

=> \(\dfrac{1,6}{3-V_1}-\dfrac{0,2}{V_1}=0,6\)

=> 1,6.V₁ - 0,2(3-V₁) = 0,6.V₁.(3-V₁)

=> 1,8.V₁ - 0,6 = 1,8.V₁ - 0,6.V₁²

=> V₁ = 1 (l) => V₂ = 2 (l)

\(\left\{{}\begin{matrix}C_{M\left(A\right)}=\dfrac{0,2}{1}=0,2M\\C_{M\left(B\right)}=\dfrac{1,6}{2}=0,8M\end{matrix}\right.\)