Question

Answer 1

+ Rút gọn A

\(=\dfrac{x+1}{x^2+x}\)

\(\)\(=\dfrac{x+1}{x\left(x+1\right)}\)

\(=\dfrac{1}{x}\)

Thay \(x=10000\) vào \(A\) ta được \(A=\dfrac{1}{10000}\)

Vậy \(\dfrac{1}{\dfrac{1}{10000}}=10000\)

Answer 2

\(A = \dfrac{x}{x^2+x} + \dfrac{1}{x^2+x} = \dfrac{x+1}{x^2+x} = \dfrac{ x + 1 }{ x( x + 1 )} = \dfrac{1}{x}\)

\( \rightarrow \dfrac{1}{A} = x \)

Thế \(x = 10000 \) vào \(\dfrac{1}{A}\) ta có :

\(\dfrac{1}{A} = 10000\)

Vậy \(\dfrac{1}{A} = 10000\) tại \(x = 10000\)