Question

Answer 1

\(=>\left[{}\begin{matrix}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{1}{2}+2=\dfrac{5}{2}\\x=\dfrac{1}{2}-2=-\dfrac{3}{2}\end{matrix}\right.\)

Answer 2

\(=>\left(x+\dfrac{1}{3}\right)^2=\dfrac{21}{2}-\dfrac{3}{2}=\dfrac{18}{2}=9\)

\(=>\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.=>\left[{}\begin{matrix}x=3-\dfrac{1}{3}=\dfrac{8}{3}\\x=-3-\dfrac{1}{3}=-\dfrac{10}{3}\end{matrix}\right.\)