\(M=3\cdot\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+...+\dfrac{1}{103}-\dfrac{1}{106}\right)\)
\(M=3\cdot\left(1-\dfrac{1}{106}\right)=3\cdot\dfrac{105}{106}=\dfrac{315}{106}\)
\(K=\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2021}-\dfrac{1}{2022}\right):2\)
\(K=\left(1-\dfrac{1}{2022}\right):2=\dfrac{2021}{4044}< \dfrac{1}{2}\)
\(B=\left(7\dfrac{4}{9}-3\dfrac{4}{9}\right)+\dfrac{51}{11}=4+\dfrac{51}{11}=\dfrac{95}{11}\)
\(A=4\dfrac{2}{5}-4\dfrac{2}{5}-3\dfrac{1}{2}=0-\dfrac{7}{2}=-\dfrac{7}{2}0-\dfrac{1}{2}4\)
