Do \(a>b\Rightarrow a-b>0\)
\(P=\dfrac{a^2+b^2-4+1}{a-b}=\dfrac{a^2+b^2-2ab+1}{a-b}=\dfrac{\left(a-b\right)^2+1}{a-b}\)
\(P=a-b+\dfrac{1}{a-b}\ge2\sqrt{\left(a-b\right).\dfrac{1}{a-b}}=2\) (đpcm)
Dấu "=" xảy ra khi \(\left(a;b\right)=\left(2;1\right);\left(-1;-2\right)\)

