\(n_{H_2}=\dfrac{6,72}{22,4}=0,3mol\)
\(\left\{{}\begin{matrix}Al:x\left(mol\right)\\Mg:y\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}27x+24y=6,3\\BTe:3x+2y=2n_{H_2}=0,6\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1mol\\y=0,15mol\end{matrix}\right.\)
\(\%m_{Al}=\dfrac{0,1\cdot27}{6,3}\cdot100\%=42,86\%\)
\(\%m_{Mg}=100\%-42,86\%=57,14\%\)

