\(n_{MgO}=\dfrac{8}{40}=0,2\left(mol\right)\)
PTHH: MgO + 2NHO3 ---> Mg(NO3)2 + H2O
0,2 0,4 0,2 0,2
\(\rightarrow\left\{{}\begin{matrix}m_{HNO_3}=63.0,4=25,2\left(g\right)\\m_{Mg\left(NO_3\right)_2}=0,2.148=29,6\left(g\right)\\m_{H_2O}=0,2.18=3,6\left(g\right)\end{matrix}\right.\)