a) Zn + 2HCl -> ZnCl2 + H2
0.15 0.3. 0.15. 0.15
b) n H2= 3.36/22.4 = 0.15 mol
m HCl = 0.3x36.5 = 10.95g
C% HCl = 10.95x100/200 = 5.475%
c) m Zn = 0.15x65 = 9.75g
m H2 = 0.15x2 = 0.3g
m ZnCl2 = 0.15x136 = 20.4g
m dd = 9.75 + 200- 0.3 = 209.45g
C% ZnCl2= 20.4x100/209.45 = 9.74%