\(=\left(\dfrac{7}{15}-\dfrac{2}{15}\right)+\left(\dfrac{5}{12}+\dfrac{7}{12}\right)=\dfrac{1}{3}+1=\dfrac{4}{3}\)
Đúng 6
Bình luận (2)
\(=\left(\dfrac{5}{12}+\dfrac{7}{12}\right)+\left(\dfrac{17}{15}-\dfrac{2}{15}\right)\)
\(=1+1\)
\(=2\)
Đúng 0
Bình luận (0)