a) \(\dfrac{11}{12}\cdot x+\dfrac{3}{4}=\dfrac{1}{6}\)
\(\dfrac{11}{12}\cdot x=\dfrac{1}{6}-\dfrac{3}{4}\)
\(\dfrac{11}{12}\cdot x=-\dfrac{7}{12}\)
\(x=-\dfrac{7}{12}\div\dfrac{11}{12}\)
\(x=-\dfrac{7}{11}\)
b) \(\dfrac{1}{2}\cdot x-\dfrac{1}{3}=-1\dfrac{3}{4}\)
\(\dfrac{1}{2}\cdot x-\dfrac{1}{3}=-\dfrac{7}{4}\)
\(\dfrac{1}{2}\cdot x=-\dfrac{7}{4}+\dfrac{1}{3}\)
\(\dfrac{1}{2}\cdot x=-\dfrac{17}{12}\)
\(x=-\dfrac{17}{12}\div\dfrac{1}{2}\)
\(x=-\dfrac{17}{6}\)
c) \(\left(\dfrac{2}{5}+x\right)\cdot\dfrac{-3}{10}=-2\dfrac{1}{5}\)
\(\left(\dfrac{2}{5}+x\right)\cdot\dfrac{-3}{10}=-\dfrac{11}{5}\)
\(\dfrac{2}{5}+x=-\dfrac{11}{5}\div\left(-\dfrac{3}{10}\right)\)
\(\dfrac{2}{5}+x=\dfrac{22}{3}\)
\(x=\dfrac{22}{3}-\dfrac{2}{5}\)
\(x=\dfrac{104}{15}\)
