bài 1 :
\(a,\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{3}{4}\\ \dfrac{1}{2}x=\dfrac{2}{3}-\dfrac{3}{4}\\ \dfrac{1}{2}x=\dfrac{-1}{12}\\ x=\dfrac{-1}{12}:\dfrac{1}{2}=\dfrac{-1}{6}\)
\(c,\dfrac{5}{4}+\dfrac{1}{4}:x=\dfrac{11}{8}\\ \dfrac{1}{4}:x=\dfrac{11}{8}-\dfrac{5}{4}\\ \dfrac{1}{4}:x=\dfrac{1}{8}\\ x=\dfrac{1}{4}:\dfrac{1}{8}\\ x=2\)