Question

Answer 1

ĐKXĐ :   \(x\ne0;x\ne2\)

\(\Leftrightarrow\dfrac{\left(x+2\right).x}{\left(x-2\right).x}-\dfrac{x-2}{x\left(x-2\right)}=\dfrac{2}{x.\left(x-2\right)}\)

\(\Leftrightarrow\left(x+2\right).x-x+2=2\)

\(\Leftrightarrow x^2+2x-x+2=2\)

\(\Leftrightarrow x^2+x=0\)

\(\Leftrightarrow x\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(KTM\right)\\x=-1\left(TM\right)\end{matrix}\right.\)

Vậy x = -1