Question

Answer 1

3Fe+2O2-to>Fe3O4

0,1-----------------1\30 mol

n Fe=0,1 mol

=>m Fe3O4=1\30.232=7,73g

 

Answer 2

Câu 6.

a/ \(n_{CH_4}=\dfrac{3,2}{16}=0,2\left(mol\right)\)

PTHH: CH₄ + 2O₂ ---t^o→ CO₂ + 2H₂O

Mol:      0,2      0,4

b/ \(V_{O_2}=0,4.22,4=8,96\left(l\right)\)

 \(\Rightarrow V_{kk}=\dfrac{8,96}{20\%}.100\%=44,8\left(l\right)\)