Question

Answer 1

\(a,M=\dfrac{1}{12}x^7y^{10}+\left(\dfrac{1}{7}x^5y^7\right)\left(-\dfrac{7}{3}x^2y^3\right)=\dfrac{1}{12}x^7y^{10}-\dfrac{1}{3}x^7y^{10}\)

b, Thay x=-1, y=-1 vào M ta có:
\(\dfrac{1}{12}x^7y^{10}-\dfrac{1}{3}x^7y^{10}=\dfrac{1}{12}.\left(-1\right)^7.\left(-1\right)^{10}-\dfrac{1}{3}.\left(-1\right)^7.\left(-1\right)^{10}=\dfrac{1}{12}.\left(-1\right).1-\dfrac{1}{3}.\left(-1\right).1=\dfrac{-1}{12}+\dfrac{1}{3}=\dfrac{1}{4}\)

Answer 2

câu kết luận là gì hả bạn