\(n_{CO_2}=\dfrac{4,4}{44}=0,1\left(mol\right)\)
\(n_{H_2O}=\dfrac{2,7}{18}=0,15\left(mol\right)\)
=> nC = 0,1 (mol); nH = 0,3 (mol)
=> \(n_O=\dfrac{2,3-0,1.12-0,3.1}{16}=0,05\left(mol\right)\)
Xét nC : nH : nO = 0,1 : 0,3 : 0,05 = 2 : 6 : 1
=> CTPT: (C2H6O)n
MA = 1,4375.32 = 46 (g/mol)
=> n = 1
=> CTPT: C2H6O
