Question

Answer 1

nCH3COOH = 30/60 = 0,5 (mol)

PTHH: CH3COOH + C2H5OH -> (H2SO4 đặc, t°) CH3COOC2H5 + H2O

nCH3COOC2H5 = 0,5 (mol)

mCH3COOC2H5 = 0,5 . 88 = 44 (g)

=> B

 

Answer 2

B

Answer 3

\(n_{CH_3COOH}=\dfrac{30}{60}=0,5mol\)

\(CH_3COOH+C_2H_5OH\rightarrow CH_3COOC_2H_5+H_2O\)

      0,5                                            0,5                        ( mol )

\(m=0,5.88=44g\)

=> Chọn B