Câu 2.
Đặt \(\left\{{}\begin{matrix}\dfrac{1}{x-2}=a\left(mol\right)\\\dfrac{1}{y-1}=b\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\)Hệ sẽ thành:
\(\left\{{}\begin{matrix}a+b=6\\2a-3b=2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=6-b\\2\left(6-b\right)-3b=2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}b=2\\a=6-2=4\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{1}{x-2}=4\\\dfrac{1}{y-1}=2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{9}{4}\\y=\dfrac{3}{2}\end{matrix}\right.\)