Question

Answer 1

\(a,\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

\(b,\dfrac{8}{7}-\dfrac{3}{5}=\dfrac{40}{35}-\dfrac{21}{35}=\dfrac{19}{35}\)

\(c,\dfrac{3}{5}\times\dfrac{6}{7}=\dfrac{18}{35}\)

\(d,\dfrac{5}{9}:\dfrac{3}{8}=\dfrac{40}{27}\)

Answer 2

a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b) \(\dfrac{8}{7}-\dfrac{3}{5}=\dfrac{40}{35}-\dfrac{21}{35}=\dfrac{19}{35}\)

c) \(\dfrac{3}{5}\) x \(\dfrac{6}{7}=\) \(\dfrac{18}{35}\)

d) \(\dfrac{5}{9}:\dfrac{3}{8}=\dfrac{5}{9}x\dfrac{8}{3}=\dfrac{5x8}{9x3}=\dfrac{40}{27}\)

Answer 3

a,\(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b,\(\dfrac{8}{7}-\dfrac{3}{5}=\dfrac{40}{35}-\dfrac{21}{35}=\dfrac{19}{35}\)

c\(\dfrac{3}{5}x\dfrac{6}{7}=\dfrac{3x6}{5x7}=\dfrac{18}{35}\)

d\(\dfrac{5}{3}:\dfrac{3}{8}=\dfrac{5}{3}x\dfrac{8}{3}=\dfrac{40}{9}\)