Thay a = \(\dfrac{-3}{7}\) ta có
\(\dfrac{-3}{7}\cdot\dfrac{1}{2}+\dfrac{-3}{7}\cdot\dfrac{1}{3}-\dfrac{-3}{7}\cdot\dfrac{1}{4}\)
\(=\dfrac{-3}{7}\cdot\left(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{3}{4}\right)\)
\(=\dfrac{-3}{7}\cdot\dfrac{7}{12}\)
\(=\dfrac{-1}{4}\)