Bài 1
a, Với x khác -2 ; 2
\(A=\left(\dfrac{x+2-x+2}{\left(x-2\right)\left(x+2\right)}\right):\dfrac{2}{x+2}=\dfrac{4\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}=\dfrac{2}{x-2}\)
b, Ta có \(A=\dfrac{2}{x-2}=2\Rightarrow2x-4=2\Leftrightarrow x=3\left(tmđk\right)\)


