Lời giải:
$|x|=\frac{1}{3}\Rightarrow x=\pm \frac{1}{3}$
Nếu $x=\frac{1}{3}; y=-3$ thì:
$A=2(\frac{1}{3})^2-3.\frac{1}{3}.(-3)+4(-3)^2=\frac{353}{9}$
Nếu $x=-\frac{1}{3}; y=-3$ thì:
$A=2(\frac{-1}{3})^2-3.\frac{-1}{3}.(-3)+4(-3)^2=\frac{299}{9}$
b.
Đặt $\frac{x}{3}=\frac{y}{5}=k\Rightarrow x=3k; y=5k$
$B=\frac{5(3k)^2+3(5k)^2}{10(3k)^2-3(5k)^2}=\frac{120k^2}{15k^2}=\frac{120}{15}=8$
