4.
\(n_{Fe}=\dfrac{m_{Fe}}{M_{Fe}}=\dfrac{22,4}{56}=0,4mol\)
\(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)
0,4 0,4 0,4 ( mol )
\(m_{FeSO_4}=n_{FeSO_4}.M_{FeSO_4}=0,4.152=60,8g\)
\(V_{H_2}=n_{H_2}.22,4=0,4.22,4=8,96l\)
5.
\(n_{Fe}=\dfrac{m_{Fe}}{M_{Fe}}=\dfrac{11,2}{56}=0,2mol\)
\(Fe_2O_3+3H_2\rightarrow\left(t^o\right)2Fe+3H_2O\)
0,1 0,3 0,2 ( mol )
\(m_{Fe_2O_3}=n_{Fe_2O_3}.M_{Fe_2O_3}=0,1.160=16g\)
\(V_{H_2}=n_{H_2}.22,4=0,3.22,4=6,72l\)
6.
\(n_{Zn}=\dfrac{m_{Zn}}{M_{Zn}}=\dfrac{6,5}{65}=0,1mol\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,1 0,1 0,1 ( mol )
\(m_{ZnCl_2}=n_{ZnCl_2}.M_{ZnCl_2}=0,1.136=13,6g\)
\(V_{H_2}=n_{H_2}.22,4=0,1.22,4=2,24l\)
7.
\(n_{H_2}=\dfrac{V_{H_2}}{22,4}=\dfrac{6,72}{22,4}=0,3mol\)
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
0,6 0,2 0,3 ( mol )
\(m_{AlCl_3}=0,2.133,5=26,7g\)
\(m_{HCl}=0,6.36,5=21,9g\)
