Câu 1.
\(ZnS+2HCl\rightarrow ZnCl_2+H_2S\)
\(2H_2S+SO_2\rightarrow3S+2H_2O\)
\(S+O_2\underrightarrow{t^o}SO_2\)
\(5SO_2+2H_2O+2KMnO_4\rightarrow2H_2SO_4+2MnSO_4+K_2SO_4\)
\(H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+H_2O+CO_2\)
\(Na_2SO_4+BaCl_2\rightarrow BaSO_4\downarrow+2NaCl\)
Câu 3.
\(\left\{{}\begin{matrix}n_{Al}=x\left(mol\right)\\n_{Zn}=y\left(mol\right)\end{matrix}\right.\)\(\Rightarrow27x+65y=11,9\left(1\right)\)
\(n_{H_2}=\dfrac{8,96}{22,4}=0,4mol\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
\(\Rightarrow3x+y=0,4\left(2\right)\)
Từ (1) và (2)\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{47}{560}\\y=\dfrac{83}{560}\end{matrix}\right.\)
a)\(m_{Al}=\dfrac{47}{560}\cdot27\approx2,27g\)
\(m_{Zn}=\dfrac{83}{560}\cdot65=9,63g\)
b)\(\%m_{Al}=\dfrac{2,27}{11,9}\cdot100\%=19,07\%\)
\(\%m_{Zn}=100\%-19,07\%=80,93\%\)
c)\(BTe:2n_{SO_2}=3n_{Al}+2n_{Zn}=3\cdot\dfrac{47}{560}+2\cdot\dfrac{83}{560}\approx0,55mol\)
\(\Rightarrow n_{SO_2}=0,275mol\Rightarrow V=6,16l\)
